[FEN "7Q/p1p1b1B1/6r1/2p3kp/4Bp1q/7P/PPP2PP1/6K1 w - - 0 1"]
(source)
In this problem, it’s White to move and mate in two. What is the solution?
[FEN "7Q/p1p1b1B1/6r1/2p3kp/4Bp1q/7P/PPP2PP1/6K1 w - - 0 1"]
(source)
In this problem, it’s White to move and mate in two. What is the solution?
I would not normally answer this, but the real answer was deleted by its author for some reason, and is hidden. I also think that the original -3 for the question was more due to the original poster not being a native English speaker so I edited that too.
This is from the game Diaz Carias-Cordovil, 1966 Olympiad. Black resigned after 30.Bh6+, which is the first move of the solution. After Black’s forced Rxh6, White will play Qe5#.
[Event "Olympiad-17 Final C"]
[Site "Havana"]
[Date "1966.11.13"]
[Round "9"]
[White "Diaz Carias, Salvador"]
[Black "Cordovil, Joao Maria"]
[Result "1-0"]
[ECO "C50"]
[StartPly "58"]
[EventDate "1966.11.04"]
[EventType "team-tourn"]
[EventRounds "13"]
[EventCountry "CUB"]
[SourceTitle "MCD"]
[WhiteTeam "Venezuela"]
[BlackTeam "Portugal"]
[WhiteTeamCountry "VEN"]
[BlackTeamCountry "POR"]
[FEN ""]
1. e4 e5 2. Nf3 Nc6 3. Bb5 Be7 4. d4 d6 5. h3 exd4 6. Nxd4 Nf6 7. Nc3 O-O 8. O-O Nxe4 9. Nxc6 bxc6 10. Nxe4 d5 11. Bd3 dxe4 12. Bxe4 Rb8 13. Qf3 c5 14. Rd1 Bd6 15. Bd2 Qh4 16. Bc3 f5 17. Bd5+ Kh8 18. Re1 f4 19. Re2 h5 20. Rae1 Bg4 21. Re6 Bxe6 22. Rxe6 Rf6 23. Qe4 Rbf8 24. Rxf6 Rxf6 25. Qe8+ Kh7 26. Qg8+ Kh6 27. Be4 Rg6 28. Qh8+ Kg5 29. Bxg7 Be7 30. Bh6+ (30. Bh6+ Rxh6 31. Qe5#) 1-0
Here is a solution in three moves.
[FEN "7Q/p1p1b1B1/6r1/2p3kp/4Bp1q/7P/PPP2PP1/6K1 w - - 0 1"]
1. Bh6+ Rxh6 2. Qg7+ Rg6 3. Qxg6# *
Bh6+ Rxh6 forced and Qe5 is then checkmate