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I want to see if a puzzle could exist where you must avoid finding mate in 1 or 2 but just find the mate in 3 solution.

This is not subjective it is a hard math problem to make a move that forces mate in 3 while avoiding other moves that force an earlier mate

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    Maybe you can express this more elegantly: a puzzle where there is a mate in 1, and mate in 2 & a mate in 3?
    – Laska
    Aug 5 at 4:28
  • Laska, Rewan, you simply could have linked to the relevant MatPlusForum thread :-) (Or do I misunderstand the intention of the author?) 8/3N1p2/8/2N2P2/p1Pk4/p2p1p2/B2PPPp1/6K1 HR, MPF May 10 2020
    – Hauke Reddmann
    Aug 7 at 10:49

1 Answer 1

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6k1/4Q3/6K1/8/8/8/8/8 w - - 0 1

Just take n moves, without threefold repetition, doing a king walk that goes back to g6 or h6. Then Qg7#. This will be your forced checkmate in n+1 moves.

EDIT:

k1B5/r2rrrrr/R7/R7/R1N5/R7/R6B/K7 w - - 0 2
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  • the solution is far from unique, though.
    – Noam D. Elkies
    Aug 5 at 23:53
  • @NoamD.Elkies The new position I added should be a unique mate in three
    – Chris Sanders
    Aug 6 at 9:35

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