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I already looked on several websites but I have not been able to get a clear and thorough answer to this question:

If player A has FIDE rating x and player B has FIDE rating y, how many times, on average, player A should be able to win? In other words, what is the probability for A to beat B?
Is there a mathematical formula to get such a probability?

Furthermore, what is the amount of points that are added/subtracted to the players if they have a certain difference in Elo rating? Which is the mathematical formula behind it?

For instance, this article All truth about ELO rating system gives a couple of examples for opponents with a rating difference of 200, 400, 600; but is there a more generic formula?

Could someone give (or point to) a quite decent and thorough explanation? Thanks in advance!

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    Welcome to Chess! Please have a look at How to calculate the FIDE Percentage Expectancy Table which may already answer your question; my answer there includes the exact formula (taken from Wikipedia).
    – Glorfindel ♦
    Commented May 6, 2019 at 18:03
  • If winning percentages could really be determined from rating differences, that would mean that if we knew A's winning percentage against B, and B's winning percentage against C, then we could determine A's winning percentage against C. I don't believe this is the case.
    – bof
    Commented May 7, 2019 at 0:15

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