# Record Swiss top tie

In a current German championship, a whopping 11 players currently have 5/6. The fact that 197 players are listed makes this a bit less remarkable, of course. Obviously, the probability p of such an event would be the most convincing record measure, but that's a tough one. I thus suggest the following approximation: Largest tie at the end of a 9 round swiss, measured by t=(tied people at the top)/(all people). (Or is there a statistical argument that I should apply some logarithms?) So we have about t~0.05 here, which should be easy to beat.

Anyway, what is the largest mass tie you recall? (Round robins would be also remarkable, but have the few players advantage in comparison here.)

• I think dividing by all people favors smaller events. For Example Carlsen - Caruana match ended in a tie for classical portion: "tied people at the top" -> 2, "all people"-> 2, 2 / 2 = 1. And 1 is the most you can get. Jul 28 at 22:06
• @Akavall Carlsen-Caruana isn't a "swiss" though.
– D M
Jul 29 at 2:26
• @Akavall: You are mathematically right, which is why I prefer limiting to Swiss (still, a 10 person round robin ending with all 4.5 would be remarkable nonetheless). Jul 29 at 7:28