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Let's say that I have a pawn at b2 and a bishop at d2 and I want to capture the pawn on c3 with my bishop. The expression I used is bc3. However, it uses my pawn at b2 to capture the pawn at c3. I then tried b2c3, but it did the same.

How do you use bishop to capture the pawn at c3 with algebraic expression in this case?

[FEN "rnbqkbnr/pppp1ppp/8/8/8/2p5/PP1BPPPP/RN1QKBNR w KQkq - 0 4"]

1.Bxc3 (1.bxc3)
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  • "I then tried b2c3, but it did the same." Well of course, because your piece on b2 is the same pawn. Did you try d2c3?
    – amalloy
    May 17 at 0:26
  • 1
    @mateenulhaq your edit makes the question contain its own answer :)
    – AakashM
    May 17 at 8:58
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The expression I used is bc3

Lowercase letters ALWAYS refer to pawns/files. Uppercase ALWAYS refers to pieces. You need to use Bxc3 for "Bishop at d2"xc3.

1
  • 20
    Lowercase letters refer to files. A pawn just doesn't have the uppercase letter.
    – user58697
    May 15 at 18:58

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