I was wondering how many queens can be put on boards without the position being a forced checkmate or a forced stalemate. The best I came up with is 53 this position.
[FEN "QQQQQRK1/QQQQQPr1/QQQQQRNk/QQQQQQpB/QQQQQQQQ/QQQQQQQQ/QQQQQQQQ/QQQQQQQQ w - - 0 1"]
Is there a way to fit 54 or more queens, given the constraints)? And if not, how would one show that more queens cannot be placed?