# What is the highest value of pieces on this particular 6x6 board, without any of them attacking each other?

I got a question in school in which I have to get the highest score possible by adding pieces on a 6x6 board like this:

The rules are that they are the same color and may never attack each other, and that pieces on my board must also be on yours in the same position.

Here are the point values:

Queen(D)15 points

Rook(R)15 points

Kings(K)10 points

Bishop(B)=9 points

Knight(H)=5 points

Pawn=0 points

My highest value was 97 by placing 8 bishops.

• yes @RewanDemontay Jan 6 '20 at 20:49
• Thanks if you could help @RewanDemontay Jan 6 '20 at 20:49
• @RewanDemontay everyone has the same question but with different pieces already placed, you also have to add the 'already placed' pieces in the endscore, my highest score was by 8 bisshops Jan 6 '20 at 20:52
• @RewanDemontay yes, thanks, I have 5 try's to enter the answer for school, but every mistake = -10 points from max 50 Jan 6 '20 at 20:55
• @PhishMaster I am not a teacher, but personally I wouldn't allow it. But a user rated in meta told me homework is allowed in the site if it shows effort. The user here has provided a 97 score answer, meanning it has made an effort not just provided an ennunciate and asked for the solution. Here a meta post that deals with it
– user18196
Jan 6 '20 at 23:16

This was the correct answer with 100 points!

• Supertuper :) Thanks for sharing and welcome to chess stack exchange.
– user18196
Jan 7 '20 at 17:16

I have found a slightly higher value of 98 by replacing a bishop with a king.

You can create images of various board sizes like this at Apronus.com.

• okay, thanks, are you sure this is the heighest? Jan 6 '20 at 21:10
• I got 98 with a different layout. Do not guarantee there is not more if I kept playing with it. Jan 6 '20 at 21:36
• @RewanDemontay I will try your answer tomorrow in school, thank you a lot! Jan 6 '20 at 21:41
• @RewanDemontay yes but I am not sure if it is the right one, if it works I will accept!, thank you! Jan 7 '20 at 7:41
• someone else came up with an idea for 100 points Jan 7 '20 at 15:38

The max is 90 +Q + K = 105 + K as I understand the problem. You can place six rooks at 15 each.

Then if you replace any of the rooks with a Q you lose two rooks by being attacked by that new queen.

I get 115 max as I can put six rooks on the board with the K and Q. And no piece is attacking any others.