# What is the highest value of pieces on this particular 6x6 board, without any of them attacking each other?

I got a question in school in which I have to get the highest score possible by adding pieces on a 6x6 board like this:

The rules are that they are the same color and may never attack each other, and that pieces on my board must also be on yours in the same position.

Here are the point values:

Queen(D)15 points

Rook(R)15 points

Kings(K)10 points

Bishop(B)=9 points

Knight(H)=5 points

Pawn=0 points

My highest value was 97 by placing 8 bishops.

• yes @RewanDemontay Commented Jan 6, 2020 at 20:49
• Thanks if you could help @RewanDemontay Commented Jan 6, 2020 at 20:49
• @RewanDemontay everyone has the same question but with different pieces already placed, you also have to add the 'already placed' pieces in the endscore, my highest score was by 8 bisshops Commented Jan 6, 2020 at 20:52
• @RewanDemontay yes, thanks, I have 5 try's to enter the answer for school, but every mistake = -10 points from max 50 Commented Jan 6, 2020 at 20:55
• @PhishMaster I am not a teacher, but personally I wouldn't allow it. But a user rated in meta told me homework is allowed in the site if it shows effort. The user here has provided a 97 score answer, meanning it has made an effort not just provided an ennunciate and asked for the solution. Here a meta post that deals with it
– user18196
Commented Jan 6, 2020 at 23:16

This was the correct answer with 100 points!

• Supertuper :) Thanks for sharing and welcome to chess stack exchange.
– user18196
Commented Jan 7, 2020 at 17:16

I have found a slightly higher value of 98 by replacing a bishop with a king.

You can create images of various board sizes like this at Apronus.com.

• okay, thanks, are you sure this is the heighest? Commented Jan 6, 2020 at 21:10
• I got 98 with a different layout. Do not guarantee there is not more if I kept playing with it. Commented Jan 6, 2020 at 21:36
• @RewanDemontay I will try your answer tomorrow in school, thank you a lot! Commented Jan 6, 2020 at 21:41
• @RewanDemontay yes but I am not sure if it is the right one, if it works I will accept!, thank you! Commented Jan 7, 2020 at 7:41
• someone else came up with an idea for 100 points Commented Jan 7, 2020 at 15:38

The max is 90 +Q + K = 105 + K as I understand the problem. You can place six rooks at 15 each.

Then if you replace any of the rooks with a Q you lose two rooks by being attacked by that new queen.

I get 115 max as I can put six rooks on the board with the K and Q. And no piece is attacking any others.