The brochure for the upcoming Oceania Zonal in Guam states:
The winners of the 2019 Guam Zonal qualify and are entitled to advance to play in the World Cup and the World Chess Championship.
I'm unclear on what exactly this means for women's chess. (Men go into the World Cup, which seems clear enough.)
Last year, WFM Kathryn Hardegen represented Australia in the November 2018 Women's World Chess Championship, and came second in the 2017 Oceania Zonal (crosstable) but the winner WFM Layla Timergazi didn't play in the Women's World Chess Championship, so Kathryn Hardegen played instead.
However, this was a knockout tournament; WFM Hardegen was knocked out by GM Ju Wenjun (who went on to win this tournament) in round 1.
However, as I understand correctly, FIDE is changing the format to no longer be a knockout tournament. Wikipedia writes:
The match marks the return to a match only format for the title with qualifying Candidates Tournament, after new FIDE president Arkady Dvorkovich expressed his dissatisfaction for the knock-out tournaments and its frequent different world champions. ... The newly established candidates tournament starts on 29 May 2019 in Kazan, Russia. The format is an eight player double round-robin tournament.
Women's World Chess Championship 2019, Wikipedia
So if the candidates tournament is an 8-player round robin, it can't have all the zonal winners.
Question: Does the winner of the women's Oceania Zonal qualify to play in a world championship match?