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I want to know what the quickest way to an en passant mate is for either side, after all other possible en passant moves by both sides have been made. This is a very complicated question, so it is okay if nobody can answer it.

EDIT: If finding the quickest way is too hard, perhaps try to find at least some kind of way.

  • Looks like impossible to answer, because of the huge number of possible variations. – user1583209 Dec 11 '18 at 20:58
  • Maybe so. But maybe instead of the fastest way, someone could at least point out some way? – Rewan Demontay Dec 11 '18 at 21:06
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    I am not even sure I understand the question. You want to construct a game, where the maximum possible number of en passant moves has been made and the last en passant move is mate? – BlindKungFuMaster Dec 12 '18 at 10:56
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    To be honest, I don't get the point of these questions. Where's the value? – fuxia Dec 12 '18 at 17:22
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    The value of it is for fun. Almost every other single kind of theoretical chess scenario has been covered. Why not make up something fresh, something new? – Rewan Demontay Dec 12 '18 at 21:09
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Here's one try:

[FEN ""]
1.d4 b5 2.d5 c5 3.dxc6 b4 4.a4 bxa3 5.b4 d5 6.b5 a5 7.bxa6 d4 8.c4 dxc3 9.h4 f5 10.h5 g5 11.hxg6 f4 12.e4 fxe3 13.g4 Bb7 14.g5 h5 15.gxh6 e5 16.Ke2 e4 17.Qe1 Bc5 18.Nh3 Bxc6 19.f4 exf3#

While this probably isn't the fastest possible, it can't get much faster. There are 8 en passants possible, and each takes 4 half moves to set up and execute (advance to 4th rank, advance to 5th rank, opponent moves pawn, capture pawn.) Those 32 half moves takes you through move 16, and you obviously need other moves somewhere to make it be a checkmate.

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