What is a more difficult problem which involves using the king to prevent castling than the following problem?
White to play and win:
[FEN "r3k3/5p2/2K2P1P/b1N1P2P/8/8/4n3/8 w q - 0 1"]
10
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7Kb7 wins. Rd8 h7 1-0. – SmallChess May 24 '18 at 7:33
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6@michaelc35 For future reference, try to make your question less ambiguous. It's unclear whether you're posting a puzzle for us to solve, or looking for a more complicated puzzle than the one you posted. – Inertial Ignorance May 24 '18 at 18:19
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3I'm looking for a more complicated puzzle than the one above which I created. An idea I have is to have the rook defended so it doesn't have to worry about being captured by the king. Another idea is to have the king move which prevents castling not be the first move of the solution. – user11382 May 24 '18 at 19:12
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In this famous problem by H. Hultberg (1944), the white king castles to prevent Black from castling:
[FEN "r3k2/1p1p2p1/2pP3p/8/8/5R2/PPPP4/4K2R - - - 0 0 "]
White to mate in two moves.
According to chess problem conventions, castling is presumed to be legal unless it's provably illegal. In this position, you can prove that at least one player has lost the right to castle, but you don't know which one. (If the white rook on f3 came from a1, the white king must have moved to let it out. If the rook on f3 is a promoted piece, it must have visited a8, e8, or f8 before escaping the 8th rank, so the black king or rook must have moved.)
1.Rhf1? fails to 1.0-0-0.
1.0-0! and 2.Rf8#, as Black is now unable to castle.
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2This is an interesting problem. I would like to see a problem where the castling rights are known at the start and castling is the only move that wins and it does so by preventing castling. – user11382 Aug 25 '18 at 20:04
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I don't understand this problem. How do we know that it's Black who has lost the right to castle, and not White (i.e. the f3-rook came from a1, White can't castle anymore, but Black can)? – Allure Sep 6 at 22:48
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@Allure When we first look at the position, we don't know which player has lost the right to castle. After White plays O-O we know it must be Black who has lost the right to castle. I don't blame you if you consider this reasoning to be specious. – bof Sep 6 at 23:42
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In the comments section of the accepted answer, the OP (I frankly don't care that they're account is gone!) asked for a castling preventing castling problem where both castle rights are known, instead of the use retrograde analysis that that answer utilizes.
As such, out of plain fun and curiosity, I have made such a problem. It can be seen in the below diagram.
[Title "White To Move And Mate In 4 Moves"]
[FEN "4k2r/2p1p2p/P1P1P2P/8/8/8/6P1/nn2K2R w Kk - 0 1"]
Clearly, in order to checkmate Black in just four moves, White's pawn must be promoted. However, if White pushes their pawn, then Black will castle and their is no mate! Thus, White must prevent Black from castling The only way to do that is with their rook.
But if White plays 1. Rf1?, then Black will play 1... Nc2+!, also preventing a mate. Therefore, White's only option to prevent Black from castling is to castle themself-1. 0-0.
Black now has three possible lines of defense that all consist of giving a check. will do a small briefing on them here:
-1... Nd2 2. a7 Nf3+ 3. Rxf3 (gxf3? 0-0!) ~ 4. a8=Q/R#
-1... Rg8 2. a7 Rxg2+ 3. Kxg2 ~ 4. a8=Q/R#
-1... Rf8 2. Rxf8+ (a7? Rxf1+ 3. Kxf1 Nd2+!) Kxf8 3. a7 ~ 4. a8=Q/R#
And there we have it, a problem where both castling rights are known and a castling to prevent castling is the only way to win!
A 3-mover version just for fun. I will not give the solution though.
[FEN "4k2r/4p1p1/1P2P3/1N6/8/8/7P/n3K2R w Kk - 0 1"]
answered Aug 27 at 23:00
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- Kb7 followed by 2. h7 (unless Black throws in a spite check with 1...Rb8+ or 1...Ra7+).
answered May 24 '18 at 18:18
