# What is the minimum number of pieces needed in a chess set to account for all possible promoted pieces?

How many pieces would be needed in a chess set where all possibilities for promoted pieces are included if pawns are no longer used after they promote?

• I was playing a game on my phone called "Really Bad Chess" the other day and would love to have this set IRL :) Probably doesn't fit in a reasonable box really nicely though. Jul 31, 2017 at 8:52

Let's count.

• 2 rooks
• 2 bishops
• 2 knights
• 1 queen
• 1 king
• (8 pawns)

• 8 rooks
• 8 bishops
• 8 knights
• 8 queens

### Total

In total you would need 40 pieces and 8 pawns for each color, so 96 units for black and white together.

Edited to bullet format to "look" better.

• Yes so 96 total pieces for white and black when including pawns as pieces.
– user11382
Jul 31, 2017 at 4:28
• No, just 64, right? Because 8 white and 8 black rooks, 8 white and 8 black bishops, 8 white and 8 black knights, and 8 white and 8 black queens. 8*8 = 64. Or did I misinterpret your question? Jul 31, 2017 at 8:37
• 8 rooks or 8 bishops or 8 knights or 8 queens (for one side) so for both sides are 64, each promotion yields only one piece. But in practical games it is hard to promote all 8 pawns for each sides. Jul 31, 2017 at 8:40
• @SorinSolberg You need to add the starting set too (i.e. you need 10 rooks, 9 queens, etc.) Jul 31, 2017 at 9:09
• Oh of course... Okay I see. Jul 31, 2017 at 11:40