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Dec 14, 2023 at 18:07 comment added Laska @Supercat thanks for this. The inequality reasoning works both horizontally & vertically. So R(n,A) =< R(n,B). There is no such inequality linking R(n,C). I am a bit unclear which diagram you are referring to. My first diagram is bqn1KN2/rrk1pB2/nb1pPp1p/p1pP1PpP/PpP3P1/1P2N1R1/4Q3/1R4B1 (Challenge 1, Type B, 32 units, White to move) but after moving White rooks & queen, it's still impossible for a king to come from or to e8. Please clarify the diagram that you are looking at. With Ra2 and WTM, the e.p. by bPb5 doesn't matter any more because 1. Ra2-a3 b4xRa3 etc i.e. the position is living
Dec 14, 2023 at 17:38 comment added supercat @Laska: It took me a moment to understand what the parentheses meant in the table. Instead of saying "implied by inequality" say "Implied by challenge 3". Also, am I missing something or would your first diagram satisfy R(3,A) if the white rooks were moved to a2 and c2, and the queen to g2? The last two moves could have been 1. Ke8 g6 2. Bf8 g5, with Black having been able to move the king back and forth as many times as needed prior to that. Because white's last move could not have been a double pawn push, the only way the game could be live would be if Black had moved last.
Dec 14, 2023 at 16:08 comment added supercat @Laska: Sounds good to me.
Dec 14, 2023 at 15:48 vote accept supercat
Dec 14, 2023 at 4:33 comment added Laska @supercat With all due respect, can you unaccept the accepted answer by Evergalo please. All the best answers to 1, 2 & 3 are in now in my own answer, which still has a smaller number of upvotes than Evergalo & Herb. I would appreciate if you can accept my own answer or suggest what needs to be done
Sep 15, 2020 at 3:06 history edited Rewan Demontay
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Apr 5, 2020 at 1:18 history edited Rewan Demontay
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Apr 6, 2018 at 11:16 history edited Laska
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Oct 14, 2017 at 15:16 comment added supercat @LocalFluff: Before asking the question, I didn't know whether the answers to #1 and #3 would be different. While it seems unlikely that #3 would be possible with all 32 pieces on the board, I still don't know if the best position for #2 would guarantee that no stalemate would ever be possible. If it wouldn't, then any answer for #3 would also hold for #2, making #2 redundant.
Oct 14, 2017 at 13:29 comment added LocalFluff You are asking three different questions, you have to delete it and post three separate questions. The questions are all so totally unrelated to each other that they must be posted on different sites in different languages at different times. The whole 1, 2, 3 thing makes me so very confused that we have to chat about it here for a long while now. I know that you know that feeling!
Oct 9, 2017 at 16:39 answer added Laska timeline score: 15
Sep 28, 2017 at 5:29 history tweeted twitter.com/StackChess/status/913274419224698880
Sep 27, 2017 at 15:15 vote accept supercat
Dec 14, 2023 at 15:48
Sep 25, 2017 at 8:18 answer added Evargalo timeline score: 11
Sep 25, 2017 at 2:28 answer added Herb timeline score: 12
Sep 25, 2017 at 1:38 comment added supercat @TMM: Positions where pieces are limited to moving back and forth would be fine, if they are reachable via sequence of legal moves.
Sep 25, 2017 at 1:20 comment added TMM What exactly are you looking for? Are positions where the pieces are arranged such that each side can only move one piece back and forth good enough? Or do the pieces need more "freedom"? If so, how much more freedom? (Such almost-stalemates are pretty easy to construct, although maybe there would not be proof games if both sides have 16 pieces.)
Sep 24, 2017 at 22:14 history asked supercat CC BY-SA 3.0